If $y = \frac{x^2}{(x - 1)(x - 2)(x - 3)} + \frac{2x}{(x - 2)(x - 3)} + \frac{3}{x - 3} + 1$,then $\frac{xy'}{y}$ is equal to (where $y' = \frac{dy}{dx}$):

  • A
    $\frac{1}{1 - x} + \frac{1}{2 - x} + \frac{1}{3 - x}$
  • B
    $\frac{x}{1 - x} + \frac{x}{2 - x} + \frac{x}{3 - x}$
  • C
    $\frac{1}{1 - x} + \frac{2}{2 - x} + \frac{3}{3 - x}$
  • D
    $\frac{1}{x - 1} + \frac{2}{x - 2} + \frac{3}{x - 3}$

Explore More

Similar Questions

Differentiate the function with respect to $x$: $(\sin x)^{x} + \sin^{-1} \sqrt{x}$.

Difficult
View Solution

Differentiate the function $y = x^{x} - 2^{\sin x}$ with respect to $x$.

If $y = [(x+1)(2x+1)(3x+1) \ldots (nx+1)]^2$,then $\frac{dy}{dx}$ at $x=0$ is

If $y=(1+x)(1+x^2)(1+x^4) \dots (1+x^{2n})$,then the value of $\frac{dy}{dx}$ at $x=0$ is

Differentiate the function with respect to $x$: $x^{x^{2}-3}+(x-3)^{x^{2}}$ for $x > 3$.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo